sebuah kerucut memiliki diameter lingkaran 60dm tinggi kerucut 45dm tentukan volume kerucut?
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[tex]\small{\boxed{\begin{aligned} \sf V &= \sf \frac{1}{3} \times \pi \times {r}^{2} \times t \\ \sf &= \sf \frac{1}{3} \times 3,14 \times {(30 \: dm)}^{2} \times 45 \: dm \\ \sf &= \sf \frac{3,14}{\cancel{3}} \times {\cancel{900} \: dm}^{2} \times 45 \: dm \\ \sf &= \sf 3,14 \times {300 \: dm}^{2} \times 45 \: dm \\ \sf &= \boxed{\red{\sf {42.390 \: dm}^{3}}} \end{aligned}}}[/tex]
Jawaban:
V = 42.390 dm³
Penjelasan dengan langkah-langkah:
d = 60 dm
r = d/2
r = 60/2
r = 30dm
t = 45 dm
V = ⅓ × π × r² × t
V = ⅓ × 3,14 × 30 × 30 × 45
V = 42.390 dm³
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